LeetCode in Racket

9. Palindrome Number

Easy

Given an integer x, return true if x is palindrome integer.

An integer is a palindrome when it reads the same backward as forward. For example, 121 is palindrome while 123 is not.

Example 1:

Input: x = 121

Output: true

Example 2:

Input: x = -121

Output: false

Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.

Example 3:

Input: x = 10

Output: false

Explanation: Reads 01 from right to left. Therefore it is not a palindrome.

Example 4:

Input: x = -101

Output: false

Constraints:

Follow up: Could you solve it without converting the integer to a string?

Solution

(define/contract (is-palindrome x)
  (-> exact-integer? boolean?)
  (if (< x 0)
      #f
      (let loop ((localX x) (rev 0))
        (if (= localX 0)
            (= rev x)
            (loop (quotient localX 10) (+ (* rev 10) (remainder localX 10)))))))